Submission #3136343

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Source Code Expand

#include<iostream>
#include<string>
using namespace std;
int main()
{
	int n;
	string s, t;
	char c[] = {'b', 'a', 'c'};
	cin >> n >> s;
	if(n % 2 == 0){
		cout << "-1" << endl;
		return 0;
	}
	int a = ((n % 6) - 1) / 2;
	for(int i = 0; i < n; i++){
		t += c[a];
		a = (a == 0 ? 2 : a - 1);
	}
	if(s == t) cout << (n-1) / 2 << endl;
	else cout << "-1" << endl;
	return 0;
}

Submission Info

Judge Result